Simplify Boolean/logical expression

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Sara Nikdel
Sara Nikdel am 14 Aug. 2020
Kommentiert: Sara Nikdel am 14 Aug. 2020
I have the following commands:
syms a b c;
S = simplify( ((a|b) | a) & (a|c) );
When I run them, it gives me the following answer:
(a | b) & (a | c)
which is correct, but it is not the simplest answer. The simplest answer is this:
a | (b & c)
For what I am working on, when 'a' appears two times, it changes the result and calculation. So I get the wrong outputs. I was wondering if there is a way to get the simplest answer such as the second one for a Boolean expression or if I can make changes to the current commands to get the second answer?
Note: This is just an example, I will have about 15-20 elements/sets in my Boolean expression.

Akzeptierte Antwort

Walter Roberson
Walter Roberson am 14 Aug. 2020
simplify(S, 'steps', 10)

Weitere Antworten (1)

Cris LaPierre
Cris LaPierre am 14 Aug. 2020
You could try using the "Steps" name-value pair
S = simplify( ((a|b) | a) & (a|c) ,"Steps",50)
  1 Kommentar
Sara Nikdel
Sara Nikdel am 14 Aug. 2020
Thank you, It worked.

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