Simplify Boolean/logical expression

I have the following commands:

syms a b c;

S = simplify( ((a|b) | a) & (a|c) );

When I run them, it gives me the following answer:

(a | b) & (a | c)

which is correct, but it is not the simplest answer. The simplest answer is this:

a | (b & c)

For what I am working on, when 'a' appears two times, it changes the result and calculation. So I get the wrong outputs. I was wondering if there is a way to get the simplest answer such as the second one for a Boolean expression or if I can make changes to the current commands to get the second answer?

Note: This is just an example, I will have about 15-20 elements/sets in my Boolean expression.

Answer 1

[Walter Roberson]

simplify(S, 'steps', 10)

[Sara Nikdel]

Thank you

Answer 2

[Cris LaPierre]

You could try using the "Steps" name-value pair

S = simplify( ((a|b) | a) & (a|c) ,"Steps",50)

[Sara Nikdel]

Thank you, It worked.