double summation. for loop

12 Ansichten (letzte 30 Tage)
Saranika Das
Saranika Das am 29 Jul. 2020
Kommentiert: Rik am 4 Aug. 2020
N = 16;
h=1/N;
b=(2/(N*200))^0.5;
c=(250000*h/(N*200))^0.5;
L=1;
xt=7/N;
syms xp m n
Fi=-((h*(b^2)/(c^2))^2)*(cos((2*m-1)*pi*xt/(2*L))*cos((2*n-1)*pi*xt/(2*L)))*((sin((2*m-1)*pi*xp*h/(2*L))*sin((2*n-1)*pi*xp*h/(2*L)))+(sin((2*m-1)*pi*xp*h/(2*L))*sin((2*n-1)*pi*xp*h/(2*L))))/(((2*m-1)*pi/(2*L))*((2*n-1)*pi/(2*L)));
for xp = 1:N
for m=1:N-1
for n=m+1:N
z(m) =subs(Bi);
z1(n) =sum(subs((z)));
end
end
B(xp)=subs(sum(z1));
end
disp(double(B'));
  5 Kommentare
Saranika Das
Saranika Das am 4 Aug. 2020
Sir I am using symbolic variables to generalize the code. I need to find the values for xp and see its variation using a plot
Rik
Rik am 4 Aug. 2020
If you need to find the values of xp, what values of F do you have?

Melden Sie sich an, um zu kommentieren.

Antworten (0)

Kategorien

Mehr zu Programming finden Sie in Help Center und File Exchange

Produkte


Version

R2013a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by