Comparing Matrices of Differing Dimensions, and Creating a New Matrix which meets a criteria

I have two row vectors: A = [1 2 2 3 4 5 6], B = [2 1 45 6]

I want all the elements of B that are bigger than A to be eliminated and a new matrix with the remaining elements to be saved.

This is what I have so far:

A(A<=B) = []

But this only works if the matrix dimensions are the same, is there any way to do this comparison and return a matrix which satisfy the condition?

Thanks, Chris

[madhan ravi]

Desired result?

[Chris Stout]

a new matrix say C = [1 2 2 3 4 5 6] i.e. elemination of 45 from B

[KSSV]

You can make dimensions equal by adding NaN's to smaller array.

A = [1 2 2 3 4 5 6] ;
B = [2 1 45 6] ; 
C = NaN(size(A)) ; 
C(1:length(B)) = B ; 
A(A<=C) =[]

[Chris Stout]

Thank you I will keep this in mind, as there is definitely multiple scenarios I can see where I will need to do this.

Answer 1

[madhan ravi]

 B(all(A(:) < B)) = []

[Chris Stout]

Thank you very much, sorry I worded my question kinda badly.