How can one create this matrix, part 2
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alpedhuez
am 24 Jul. 2020
Bearbeitet: Bruno Luong
am 25 Jul. 2020
In the previous post, I have learned that
[X, Y] = meshgrid(0:.1:0.5);
[X(:), Y(:)]
will create a matrix
0 0
0 0.1
0 0.2
...
Now I want to generalize to
[X, Y, Z] = meshgrid(0:.1:0.5);
[X(:), Y(:), Z(:)]
and it creates a matrix
ans = 216×3
0 0 0
0 0.1000 0
0 0.2000 0
0 0.3000 0
0 0.4000 0
0 0.5000 0
0.1000 0 0
0.1000 0.1000 0
0.1000 0.2000 0
0.1000 0.3000 0
But the matrix I want to create is like
0 0 0
0 0 0.1
0 0 0.2
0 0 0.3
0 0 0.4
0 0 0.5
0 0.1 0.1
0 0.1 0.2
0 0.1 0.3
Please advise.
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madhan ravi
am 24 Jul. 2020
[X, Y, Z] = ndgrid(0:.1:0.5);
[Z(:), Y(:), X(:)]
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Bruno Luong
am 25 Jul. 2020
Bearbeitet: Bruno Luong
am 25 Jul. 2020
Because NDGRID returns result such that the first input change first (more rapidly) and you want the opposite, X change most slowly. Actually the code as written by madhan is confusing, it's clearer this way to me:
[Z,Y,X] = ndgrid(0:.1:0.5);
[X(:), Y(:), Z(:)]
You'll see if 1D-grid of X, Y, Z are different and not all equal to 0.0.1:0:5, it makes a whole world less confusing.
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