How to split a huge string array efficently
Ältere Kommentare anzeigen
Hi everyone,
I'm trying to split a huge string (~8.5mb, ~11.500 rows x ~400 columns) efficiently, but I cannot do that without a quiet slow "for" loop I cannot remove.
The number of colums may change from a file to another one so it's not possible for me to determin initially a unique format of the file and then import it according to it.

%% getting data from .txt => really fast
tic
disp('importing file');
a = string(textread([pwd '\test.txt'],'%s','headerlines',1)); %#ok<*DTXTRD>
toc
%% splitting each row in colums by delimiter ";" => slow
tic
disp('splitting each row by ";"');
b = strings(length(a),length(strsplit(a(1),';')));
for k=1:length(a)
b(k,:) = strsplit(a(k),';');
end
toc
%% date(str) to datenum => really fast
tic
disp('conv date to datenum');
dat1 = datenum(b(:,1),'yyyy-mm-dd');
toc
%% str to logical => really fast
tic
disp('converting data to logical array')
dat2 = logical(strcmp(b(:,2:end),'1')); %super fast
%dat2 = str2double(b(:,2:end)); %very slow
toc
% disp('converting data to logical array - 2'); %super fast as well
% tic
% dat2 = zeros(size(b));
% dat2(strcmp(b(:,2:end),'1')) = 1;
% toc
Thanks everyone! :)
Source file sample

3 Kommentare
Walter Roberson
am 24 Jul. 2020
Why not use readtable() ?
I would also point out that textscan() can process character vectors in which the lines are separated by newlines.
endystrike
am 24 Jul. 2020
endystrike
am 24 Jul. 2020
Akzeptierte Antwort
Weitere Antworten (0)
Kategorien
Mehr zu Dates and Time finden Sie in Hilfe-Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!