RR=5;
RS=750:150:3600;
for i=1:length(RS)
k(i)=RR.*RS(i)
end
am i not supposed to get the answer k(i) in the form of matrix ?
Here RS is matrix of size 1*20.
if i want to get k(i) in terms of 1*20 , what shall i do ? Please tell me. Thankyou.

 Akzeptierte Antwort

Alan Stevens
Alan Stevens am 22 Jul. 2020

0 Stimmen

k is 1x20
>> RR=5;
RS=750:150:3600;
for i=1:length(RS)
k(i)=RR.*RS(i);
end
>> k
k =
Columns 1 through 11
3750 4500 5250 6000 6750 7500 8250 9000 9750 10500 11250
Columns 12 through 20
12000 12750 13500 14250 15000 15750 16500 17250 18000

3 Kommentare

Asif Rashid
Asif Rashid am 22 Jul. 2020
Thankyou for correcting me. its working with k .
can you please tell me that why k(i) is a scalar and k be a matrix ? im confused. Thankyou
Alan Stevens
Alan Stevens am 22 Jul. 2020
k(i) simply identifies the i'th value of vector k. i.e. it is a single element of k.
Asif Rashid
Asif Rashid am 22 Jul. 2020
Alright Sir, Thankyou

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