Filter löschen
Filter löschen

Can a descriptor state space change into transfer function representaion?

1 Ansicht (letzte 30 Tage)
I have dss model be changed into transfer function form like transfer function
A=[-10 -35 -50 -24;1 0 0 0;0 1 0 0; 0 0 1 0 ];
B=[1 0; 0 1; 1 1; 1 0];
C=[1 -1 0 1;0 1 1 1];
E=eye(4);
D=0;
H=dss(A,B,C,D,E);

Akzeptierte Antwort

Star Strider
Star Strider am 21 Jul. 2020
Bearbeitet: Star Strider am 21 Jul. 2020
The easiest way to determine that (or anything else that is not explicitly documented) is to try it and see the result.
A=[-10 -35 -50 -24;1 0 0 0;0 1 0 0; 0 0 1 0 ];
B=[1 0; 0 1; 1 1; 1 0];
C=[1 -1 0 1;0 1 1 1];
E=eye(4);
D=0;
H=dss(A,B,C,D,E);
figure
bode(H)
Htf = tf(H);
figure
bode(Htf)
These seem to be the same to me.
EDIT — (21 Jun 2020 at 20:15)
The ‘Htf’ transfer functions are:
Htf =
From input 1 to output...
2 s^3 - 64 s^2 + 95 s + 110
1: ---------------------------------
s^4 + 10 s^3 + 35 s^2 + 50 s + 24
2 s^3 + 22 s^2 + 7 s + 38
2: ---------------------------------
s^4 + 10 s^3 + 35 s^2 + 50 s + 24
From input 2 to output...
-s^3 - 94 s^2 - 13 s + 45
1: ---------------------------------
s^4 + 10 s^3 + 35 s^2 + 50 s + 24
2 s^3 + 22 s^2 + 6 s + 21
2: ---------------------------------
s^4 + 10 s^3 + 35 s^2 + 50 s + 24
Continuous-time transfer function.
Different format, same result.
.

Weitere Antworten (0)

Kategorien

Mehr zu Composite Interfaces finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by