Solve "Index exceeds the number of array elements (1)", "Vectors must be the same length." errors
Ältere Kommentare anzeigen
I'd like to solve those problems from under coding using A, B, and C relationships. If equation error can't be fixed, "B(i+1)=B(i)+((h.*q)/(k*T*E))*C(i)" can be used.
a = 0;
b = 1;
n = 110;
k = 8.61733*10^(-5);
T = 300 ;
q = 1.60218*10^(-19);
E = 8.8542*10^(-12)
x= linspace(a,b,n);
h= x(2)-x(1);
A = zeros(size(x));
B = zeros(size(x));
for i = 0:n-1
A(0)=3;
B(0)=1;
C(i)=2*x(i)+3;
A(i+1)=A(i)-h.*B(i)-(0.5.*h.^2*q.*C(i))./(k*T*E);
B(i+1)=B(i)+((h.*q)/(k*T*E))*0.5*(C(i)+C(i+1));%equation error
end
plot(transpose(x),A,'.')
1 Kommentar
Tanmay Das
am 15 Jul. 2020
Hi. Can you please try starting the index from 1 instead of 0 and go upto n in the for loop?
Akzeptierte Antwort
Weitere Antworten (1)
Tanmay Das
am 15 Jul. 2020
Hi,
I have the understanding that you are facing trouble in indexing of arrays. Unlike C++ or Python, indexing starts from 1 in MATLAB. So if you write A(0), then it will throw error. The following code may be useful for your understanding:
a = 0;
b = 1;
n = 110;
k = 8.61733*10^(-5);
T = 300 ;
q = 1.60218*10^(-19);
E = 8.8542*10^(-12)
x= linspace(a,b,n);
h= x(2)-x(1);
A = zeros(size(x));
B = zeros(size(x));
A(1)=3;
B(1)=1;
C = 2*x + 3
for i = 1:n-1
A(i+1)=A(i)-h.*B(i)-(0.5.*h.^2*q.*C(i))./(k*T*E);
B(i+1)=B(i)+((h.*q)/(k*T*E))*0.5*(C(i)+C(i+1));%equation error
end
plot(transpose(x),A,'.')
Also please note that similar operations on each element of array can be done at once in MATLAB and do not require to run a loop like in case of C.
C = 2*x + 3
Hope that helps!
1 Kommentar
sookyung Kang
am 16 Jul. 2020
Bearbeitet: sookyung Kang
am 16 Jul. 2020
Kategorien
Mehr zu Matrix Indexing finden Sie in Hilfe-Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!