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How to solve this question? Help :'(

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raizo dono
raizo dono am 30 Jun. 2020
Kommentiert: Rik am 30 Jun. 2020
Question 4 (20 marks)
Laplace’s equation: Determine the distribution of temperature in a rectangular plane section, subject to a temperature distribution around its edges as follows:
The section shape, the boundary temperature distribution section and two chosen nodes are shown in the figure.
The temperature distribution is described by Laplace’s equation. Solving this equation by the finite difference method to nodes 1 and 2 of the mesh shown in the figure. This gives
(233.33 +T2 + 0 100 - 4T1)/h^2 = 2
(333.33 + 250 + 0 + T1 - 4T2)/h^2 = 2
where and are the unknown temperatures at nodes 1 and 2, respectively, and
Rearranging these equations gives
[(-4&1@1&-4)][(T_1@T_2 )]=[(-333.33@-583.33)][(-4&1@1&-4)][(T_1@T_2 )]=[(-333.33@-583.33)]
Solving this equation, we have and .
If we require a more accurate solution of Laplace’s equation, then we must use more nodes and the computation burden increases rapidly. Write a MATLAB script to solve the Laplace’s equation for any number of nodes in a square domain only. Run your codes for number of nodes
  4 Kommentare
Rik
Rik am 30 Jun. 2020
What is your question? When I run your code I get an output.
You can find guidelines for posting homework on this forum here. Please use the tools explained on this page to make your question more readable and attach the ellipgen function as an m file.
raizo dono
raizo dono am 30 Jun. 2020
Bearbeitet: raizo dono am 30 Jun. 2020
The ellipgen and Untitled5 file that I attached earlier is the halfway answer for the question. What I am trying to find is how to run codes for number of nodes n=50, 100 and 150. I cannot find any solution for this. Attached is the m file for the ellipgen

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Rik
Rik am 30 Jun. 2020
You should learn about the linspace function. I would also suggest you check if you have x and y correct. I kept your convention.
You were also limiting the axis so changing the number of nodes doesn't behave as expected.
Lx = 3; Ly = 2;
nx = 120; ny = 12; hx = Lx/nx; hy = Ly/ny;
by0 = linspace(0,Lx,nx+1); %by0 = 0*[0:hx:Lx];
byn = 200+(100/3)*linspace(0,Lx,nx+1).^2; %byn = 200+(100/3)*[0:hx:Lx].^2;
bx0 = 100*linspace(0,Ly,ny+1); %bx0 = 100*[0:hy:Ly];
bxn = 250*linspace(0,Ly,ny+1); %bxn = 250*[0:hy:Ly];
F = zeros(nx+1,ny+1); G = F;
a = ellipgen(nx,hx,ny,hy,G,F,bx0,bxn,by0,byn);
aa = flipud(a); colormap(gray)
surfl(aa)
xlabel('x direction')
ylabel('y direction')
zlabel('Temperature')
axis([0 nx 0 ny 0 500]) %axis([0 12 0 12 0 500])
  2 Kommentare
raizo dono
raizo dono am 30 Jun. 2020
So, how do I unlimit the axis to change the node numbers as asked in the question?
Rik
Rik am 30 Jun. 2020
I already edited that line for you. The only thing that is left for you is to figure out how you can run the same code with different inputs. Hint: use a for-loop, wrap your code in a function, or both.

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