How to Plot Stress Contour??

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Shubhang Jain
Shubhang Jain am 28 Jun. 2020
Kommentiert: darova am 4 Jul. 2020
I am a beginner , My doubt is that I have to Plot Stress Contour of tapered cantilever beam analysed using FEA now I have the value of element Stresses like sigmax , sigmay , tauxy ? How to proceed ?? Please Help..
  11 Kommentare
darova
darova am 1 Jul. 2020
Bearbeitet: darova am 1 Jul. 2020
Here is an example using pcolor
[x,y] = meshgrid(-2:0.1:2);
stress = x.^2+y.^2;
pcolor(x,y,stress)
Shubhang Jain
Shubhang Jain am 1 Jul. 2020
Sigma_X, Sigma_Y , Tau_XY are the stress components values at each nodes (18) in this case . X and Y axis are the boundary of the problem .

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Antworten (1)

darova
darova am 1 Jul. 2020
Reshape your data to create a matrix
stress = reshape(Sigma_X,6,3);
And use pcolor
[x,y] = meshgrid(1:3,1:6);
Sigma_X = 1.0e+03 * [-4299.57587958638 -3965.44553517593 -3204.63754334495 -2292.69609509300 -1230.97384069952 -654.515387137445 7.73070496506989e-12 8.64019966684282e-12 1.11413100967184e-11 1.02318153949454e-11 2.84217094304040e-12 -1.93267624126747e-12 4299.57587958640 3965.44553517595 3204.63754334497 2292.69609509302 1230.97384069952 654.515387137441];
Sigma_Y = [-321.901962451787 -171.276004860075 -78.8000793342068 -101.167806049306 -108.580704946648 -151.775909194735 -43.0911561819484 -52.5066078518920 -96.8460482931672 -92.9813362559606 -169.657107326625 -285.121579205828 235.719650087890 66.2627891562907 -114.892017252128 -84.7948664626148 -230.733509706602 -418.467249216922];
Tau_XY =[ -795.818460340878 -847.839977192489 -889.271783271534 -792.615142694200 -700.220084886960 -693.891956884487 -669.856459330285 -655.783844638485 -684.491978609799 -643.356643356871 -610.298792117163 -661.157024793497 -543.894458319692 -463.727712084480 -479.712173948064 -494.098144019542 -520.377499347365 -628.422092702508] ;
stress = reshape(Sigma_X,6,3);
pcolor(x,y,stress)
  2 Kommentare
Shubhang Jain
Shubhang Jain am 3 Jul. 2020

Thanks for the tip . It really helped .

darova
darova am 4 Jul. 2020

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