Put every 3 data points in matrix A into a separate row in matrix B.

Hi,

I have the following column vector called A:

1

2

3

4

5

6

7

8

9

What I want is a code that will take every 3 data points in A and put it in its own separate row in a new matrix called B. After the first 3 elements or data points in A has been selected and placed in the first row in B, the code should then select the next 3 data points and place them in the 2nd row in B and so on.

e.g., the 1st row in B will be 1,2,3, & 2nd row will be 4,5,6, & 3rd row will be 7,8,9 and so on until every 3 data points in A has been selected and placed in its own row in B.

Please see the attached image.

Thank you.

[KSSV]

What have you attempted so far?

[Curious Mind]

Thanks @KSSV for your message. I have something like this in mind, B = A(1:3:end) but this will select every 3rd element. I want to select 1 through 3.

[dpb]

No, you don't really want to "select" at all...all you're doing is rearranging.

Think about how and the solution should become apparent.

One line will do the dirty...

Answer 1

[KSSV]

A = 1:9 ; 
iwant = reshape(A,3,3)' ;