How to fill a matrix column by column better than by a for loop?
7 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Ulrich Becker
am 26 Jun. 2020
Kommentiert: Tommy
am 27 Jun. 2020
Want to parametrize areas for plotting/numerical integration/whatnot.
E.g. x-values: 0..1
y-values: x-1 ... x^3+1
This does the job, but it is awful:
xx=0:0.1:1;
nxx=length(xx);
nyy=10;
xm=repmat(xx',1,nyy);
ym=zeros(nxx,nyy);
for ii=1:nxx
xii=xx(ii);
ym(ii,:)=linspace(xii-1,xii^3+1,nyy);
end
Thanks in advance!
0 Kommentare
Akzeptierte Antwort
Tommy
am 26 Jun. 2020
How about something like this?
xx = 0:0.1:1;
nxx = numel(xx);
nyy = 10;
xm = repmat(xx',1,nyy);
base = linspace(0,1,nyy);
starts = xx-1;
stops = xx.^3+1;
ym = starts(:) + base.*(stops(:)-starts(:));
Credit to the following answer:
2 Kommentare
Weitere Antworten (1)
Ulrich Becker
am 26 Jun. 2020
Bearbeitet: Ulrich Becker
am 26 Jun. 2020
1 Kommentar
Tommy
am 27 Jun. 2020
Nice and neat, thanks for this! In case anyone reading isn't already aware:
a=[1;2;3] % is a column vector
a(:) % is still a column vector
Siehe auch
Kategorien
Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!