Index a number of coordinates as vertex(1), vertex(2), ... vertex(n) by using a for loop and vertex(n) = [x(1,n) y(1,n)]
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Sam Pomajevich
am 24 Jun. 2020
Bearbeitet: Aditya Gupta
am 24 Jun. 2020
I am trying to index the vertices as vertex(1) ,vertex(2), vertex(n), but I have not been successful. Can I achieve this in the below for loop? Or do I need a seperate for loop? Currently when run, this section reads the error:
"Unable to perform assignment because the indices on the left side are not compatible with the size of the right side."
No_vertices = input('Enter number of vertices: ');
for n = 1:No_vertices
x(1,n) = input('Enter x-coordinate:');
x(n) = x(1,n);
y(1,n) = input('Enter y-coordinate:');
y(n) = y(1,n);
vertex(n) = [x(n) y(n)];
n = n + 1;
end
Here, I enter the number of vertixes in a polygon, the for loop allows me to enter the x and y coordinates for the number of vertices I input. The x and y coordinates are stored and able to be used later as x(1), x(2), .. x(n) and y(1), y(2), ...y(n).
0 Kommentare
Akzeptierte Antwort
Aditya Gupta
am 24 Jun. 2020
Bearbeitet: Aditya Gupta
am 24 Jun. 2020
Are you perhaps trying to do something like this?
No_vertices = input('Enter number of vertices: ');
x = zeros(1,No_vertices);
y = zeros(1,No_vertices);
vertex = zeros(2,No_vertices);
for n = 1:No_vertices
x(1,n) = input('Enter x-coordinate:');
y(1,n) = input('Enter y-coordinate:');
vertex(1,n) = x(1,n);
vertex(2,n) = y(1,n);
end
You don't need to increment iterator of the for loop, "for" does that automatically.
Otherwise, I do not understand what you were trying to do.
0 Kommentare
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!