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find a row with all elements satisfying a condition

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Alon Osovsky
Alon Osovsky am 24 Jun. 2020
Kommentiert: Alon Osovsky am 24 Jun. 2020
I have a matrix that looks something like this:
mat = [20, 3; 43 0; 8 3; 100 3; 3 9];
I want to find the rows of the matrix that all of its elements are satisfying a certain condition. For example, if the condition is:
> 10
The result matrix will be:
[8 3; 3 9];
Because those are the only rows in the matrix that both of their elements are smaller then 10. Is there an easy way to achieve this result? Thanks!

Antworten (1)

Aakash Mehta
Aakash Mehta am 24 Jun. 2020
Bearbeitet: Aakash Mehta am 24 Jun. 2020
mat = [20, 3; 43 0; 8 3; 100 3; 3 9];
You can use the below code to get rows which satisy the condition.
size1 = size(mat);
vec = zeros(size1(1),1);
for i = 1:size1(1)
vec(i) = all(mat(i,:)<10);
end
extract those rows in the resultant matrix.
result = mat(vec==1, :);
  1 Kommentar
Alon Osovsky
Alon Osovsky am 24 Jun. 2020
I'm searching for a simpler solution (using already existing functions), without a for loop.

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