Problem in summation with floor function
3 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
I would like to compute the summation involving ''floor function'' as the limit of the sum. Below I have the code. But when I run that some error is apparing which is beyond my understanding. Please somebody help me to solve that issue.
" Error using symengine
Nonnegative integer or a symbol expected.
Error in sym/symsum (line 70)
rSym = mupadmex('symobj::map',fsym.s,'symobj::symsum',x.s,a.s,b.s);
Error in floorfu (line 43)
s23p=symsum(symsum(ss3p.*s2p,l,0,m),k,0,n);"
clc;
syms theta k l p q
W=1.0;
g=0.0001;
lm=0.1;
assume(k>=0);
assume(l>=0);
assume(p>=0);
assume(q>=0);
n=6;
m=6;
t1=floor((k+1)./2); %%%%%%%%%%%%% Floor fun
t2=floor(l./2);
theta=pi./3;
om=sqrt(((W).^2)-(4.*(g.^2)));
mu=sqrt((W+om)./(2.*om));
nu=((W-om)./(2.*g)).*mu;
eta=(((lm)./((2.*g)+W)).*(1+((W-om)./(2.*g)))).*mu;
tau= mu + nu.*cos(2.*theta);
d=k+l-2.*p-2.*q-2;
ag= eta.*cos(theta)./(sqrt(mu.*tau));
s1p=(mu./tau).*((-1).^m).*((1i)^(m+n)).*(2.*eta.*(mu-nu)./(sqrt(2.*mu.*nu))).^(m+n);
s2p=(((nu./2.*eta).*sqrt(mu.*tau)./(mu-nu)).^(k+l)).*factorial(k).*factorial(l).*nchoosek(n,k).*nchoosek(m,l).*exp(1i.*theta.*(k-l));
s3p= ((2./nu.*tau).^(p+q)).*factorial(2.*p + 2.*q +1 -k -l)./(factorial(p).*factorial(q)).*nchoosek(p,k-p).*nchoosek(q,l-q).*exp(-2.*1i.*theta.*(p-q)).*hermiteH(d,ag);
ss3p=symsum(symsum(s3p,q,t2,m),p,t1,n); %%%%%%%%% Actually in this line that error is coming
s23p=symsum(symsum(ss3p.*s2p,l,0,m),k,0,n);
sumout=s1p.*s23p
8 Kommentare
Ameer Hamza
am 24 Jun. 2020
For example, if you have a summation like this

following shows how to use symbolic toolbox or the sum() function using floating-point numbers
syms k
n = 10;
y = k^2*sin(k);
y1 = double(symsum(y, k, 1, n));
kv = 1:n;
y2 = sum(kv.^2.*sin(kv));
Antworten (0)
Siehe auch
Kategorien
Mehr zu Conversion Between Symbolic and Numeric finden Sie in Help Center und File Exchange
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!