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Make graph using different x value compared to integral equation

1 Ansicht (letzte 30 Tage)
sookyung Kang
sookyung Kang am 14 Jun. 2020
syms x f
a = 1.27;
b = 0.19 ;
c = 0.44 ;
d = 0.2 ;
e = 300 ;
w = i*e*log(2);
f = 5*10^21 ;
g = 2*10^23 ;
h1= linspace (0.2, 1.7);
k1 = linspace (0, 1.5);
i = 8.61733*10^(-5);
j = 2*10^21;
B1 = 0.085 ;
A1 = j.*(f/g).^((i.*e)/(4*B1)).*((2*B1.^2)./((2*B1)-(i.*e))).*exp(-(1/(2*B1)).*(a-k1-((b.^2)./(4*B1))));
P1 = (1./sqrt(2*b.^2*pi)).*exp(-((x+w)+((b.^2)./(2*B1))-a).^2./(2*b.^2));
F1 = (2*exp((h1-(x+w))./(i.*e)))./(1+2*exp((h1-(x+w))./(i.*e))+exp(((2*h1)-(2*(x+w))-d)./(i.*e)));
D1 = A1.*((2./F1).^((i.*e)./(2*B1))).*P1 ;
P11 = (1./sqrt(2*b.^2*pi)).*exp(-((x-d-w)+((b.^2)./(2*B1))-a).^2./(2*b.^2));
F11 = (2*exp((h1-(x-d-w))./(i.*e)))./(1+2*exp((h1-(x-d-w))./(i.*e))+exp(((2*h1)-(2*(x-d-w))-d)./(i.*e)));
D11 = A1.*((2./F11).^((i.*e)./(2*B1))).*P11;
f = (A1.*((2./F1).^((i.*e)./(2*B1))).*P1)+(A1.*((2./F11).^((i.*e)./(2*B1))).*P11);
F(x) = int(f,x,[0 1.7]);
plot(F,[0 1.7],'k'); xlabel('x'), ylabel ('y'); xlim([0,1.7]); ylim([10^15,10^20]); set(gca, 'YScale','log');set(gca, 'XScale','linear');
I'd like to obtain different graph compared to integral's x: x into h1-k1.
How can I solve this coding problem?

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