Hi
Lets say I have a vector that goes: [x y z]
Im trying to create, if possible without a loop, the following vec: [1:x, 1:y, 1:z]
only I don't know who x y or z will ne, or how many elemnts will the first vec have

2 Kommentare

What's wrong with your solution:
[1:x, 1:y, 1:z]
?
Maya Harel
Maya Harel am 9 Jun. 2020
the problem is that I don't define how many elements the first vec will have, It will ne detarmined randomly

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Stephen23
Stephen23 am 9 Jun. 2020
Bearbeitet: Stephen23 am 9 Jun. 2020

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Method one: nonzeros:
vec = [x,y,z];
tmp = 1:max(vec);
new = nonzeros((tmp(:)<=vec).*tmp(:)).' % requires >=R2016b
Method two: arrayfun:
new = cell2mat(arrayfun(@(n)1:n,vec,'uni',0))

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David Hill
David Hill am 9 Jun. 2020
Bearbeitet: David Hill am 9 Jun. 2020

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Misread

1 Kommentar

Maya Harel
Maya Harel am 9 Jun. 2020
thank you, but I think I didn't make myself clear, I mean that I want the new vec to go like the following exemple:
oldVec = [3,4,2]
newVec = [1,2,3,1,2,3,4,1,2]

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