How to compute centered moving average from an NxM array

5 Ansichten (letzte 30 Tage)
Poulomi Ganguli
Poulomi Ganguli am 7 Jun. 2020
Bearbeitet: Rik am 7 Jun. 2020
Hello:
I have an 40x2 matrix, in which the first column shows day index and the 2nd column value for each day:
1 11
2 12
3 10
4 10
5 12
6 11
7 12
8 10
9 12
10 10
11 12
12 12
13 10
14 9
15 12
16 12
17 12
18 11
19 10
20 10
21 11
22 11
23 10
24 8
25 9
26 9
27 9
28 8
29 8
30 12
31 11
32 9
33 9
34 12
35 11
36 11
37 10
38 10
39 11
40 9
How to compute centered moving average with 30 days moving window taking 15th of the day as the midpoint and traversing backward 14 days and forward 15 days? Basically I want to compute: Xavg = median[X(i-14):X(i+15)]. where X(i) is the data point and Average is the averaging operator. I found a few thread using convolution operator but could not find out how to fix step size since my mid point is located on the 15th day and further how to compute median effect?

Akzeptierte Antwort

Ameer Hamza
Ameer Hamza am 7 Jun. 2020
You can use movmean() and discard the endpoints
M = [
1 11
2 12
3 10
4 10
5 12
6 11
7 12
8 10
9 12
10 10
11 12
12 12
13 10
14 9
15 12
16 12
17 12
18 11
19 10
20 10
21 11
22 11
23 10
24 8
25 9
26 9
27 9
28 8
29 8
30 12
31 11
32 9
33 9
34 12
35 11
36 11
37 10
38 10
39 11
40 9];
avg_val = movmean(M(:,2), 30, 'Endpoints', 'discard')
  2 Kommentare
Poulomi Ganguli
Poulomi Ganguli am 7 Jun. 2020
Hi, I am running MATLAB 2015 movmean operator is not available.
Ameer Hamza
Ameer Hamza am 7 Jun. 2020
Alternative options
avg_val = conv(M(:,2), ones(1,30)/30, 'valid');
or
avg_val = filter(ones(1,30)/30, 1, M(:,2));
avg_val(1:29) = [];

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Rik
Rik am 7 Jun. 2020
Bearbeitet: Rik am 7 Jun. 2020
You can use a convolution with a flat array as the second input.
avg_val = convn(M(:,2), ones(30,1)/30, 'valid');

Kategorien

Mehr zu Matrices and Arrays finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by