How to compute centered moving average from an NxM array
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Poulomi Ganguli
am 7 Jun. 2020
Bearbeitet: Rik
am 7 Jun. 2020
Hello:
I have an 40x2 matrix, in which the first column shows day index and the 2nd column value for each day:
1 11
2 12
3 10
4 10
5 12
6 11
7 12
8 10
9 12
10 10
11 12
12 12
13 10
14 9
15 12
16 12
17 12
18 11
19 10
20 10
21 11
22 11
23 10
24 8
25 9
26 9
27 9
28 8
29 8
30 12
31 11
32 9
33 9
34 12
35 11
36 11
37 10
38 10
39 11
40 9
How to compute centered moving average with 30 days moving window taking 15th of the day as the midpoint and traversing backward 14 days and forward 15 days? Basically I want to compute: Xavg = median[X(i-14):X(i+15)]. where X(i) is the data point and Average is the averaging operator. I found a few thread using convolution operator but could not find out how to fix step size since my mid point is located on the 15th day and further how to compute median effect?
0 Kommentare
Akzeptierte Antwort
Ameer Hamza
am 7 Jun. 2020
You can use movmean() and discard the endpoints
M = [
1 11
2 12
3 10
4 10
5 12
6 11
7 12
8 10
9 12
10 10
11 12
12 12
13 10
14 9
15 12
16 12
17 12
18 11
19 10
20 10
21 11
22 11
23 10
24 8
25 9
26 9
27 9
28 8
29 8
30 12
31 11
32 9
33 9
34 12
35 11
36 11
37 10
38 10
39 11
40 9];
avg_val = movmean(M(:,2), 30, 'Endpoints', 'discard')
2 Kommentare
Ameer Hamza
am 7 Jun. 2020
Alternative options
avg_val = conv(M(:,2), ones(1,30)/30, 'valid');
or
avg_val = filter(ones(1,30)/30, 1, M(:,2));
avg_val(1:29) = [];
Siehe auch
Kategorien
Mehr zu Matrices and Arrays finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!