How to plot this code correctly?

5 Ansichten (letzte 30 Tage)
Jay
Jay am 21 Nov. 2012
tt=1000;
B=1700;
b=0.0013;
sigma=0.0099;
t = 0 : 1 : tt;
for K = 1 : length(t)
p(K) = (B-(b*t(K)))/(sigma);
end
p(K)= roundn(p,-1);
p(K)=p;
if p==0.0
l=.5*k;
elseif p==0.1
l=.5478*k;
elseif p==0.2
l=.5793*k;
elseif p==0.3
l=.6255*k;
elseif p==0.4
l=.6554*k;
elseif p==0.5
l=.6985*k;
elseif p==0.6
l=.7257*k;
elseif p==0.7
l=.7642*k;
elseif p==0.8
l=.7881*k;
elseif p==0.9
l=.8212*k;
elseif p==1.0
l=.8413*k;
elseif p==1.1
l=.8686*k;
elseif p==1.2
l=.8849*k;
elseif p==1.3
l=.9066*k;
elseif p==1.4
l=.9192*k;
elseif p==1.5
l=.9357*k;
elseif p==1.6
l=.9452*k;
elseif p==1.7
l=.9573*k;
elseif p==1.8
l=.9641*k;
elseif p==1.9
l=.9726*k;
elseif p==2.0
l=.9772*k;
elseif p==2.1
l=.9830*k;
elseif p==2.2
l=.9861*k;
elseif p==2.3
l=.9898*k;
elseif p==2.4
l=.9918*k;
elseif p==2.5
l=.9941*k;
elseif p==2.6
l=.9953*k;
elseif p==2.7
l=.9967*k;
elseif p==2.8
l=.9974*k;
elseif p==2.9
l=.9982*k;
elseif p==3.0
l=.9987*k;
elseif p>3.0
l=1*k;
elseif p==-0.1
l=.4522*k;
elseif p==-0.2
l=.4207*k;
elseif p==-0.3
l=.3745*k;
elseif p==-0.4
l=.3446*k;
elseif p==-0.5
l=.3015*k;
elseif p==-0.6
l=.2743*k;
elseif p==-0.7
l=.2358*k;
elseif p==-0.8
l=.2119*k;
elseif p==-0.9
l=.1788*k;
elseif p==-1.0
l=.1587*k;
elseif p==-1.1
l=.1314*k;
elseif p==-1.2
l=.1151*k;
elseif p==-1.3
l=.0934*k;
elseif p==-1.4
l=.0808*k;
elseif p==-1.5
l=.0643*k;
elseif p==-1.6
l=.0548*k;
elseif p==-1.7
l=.0427*k;
elseif p==-1.8
l=.0359*k;
elseif p==-1.9
l=.0274*k;
elseif p==-2.0
l=.0228*k;
elseif p==-2.1
l=.0170*k;
elseif p==-2.2
l=.0139*k;
elseif p==-2.3
l=.0102*k;
elseif p==-2.4
l=.0082*k;
elseif p==-2.5
l=.0059*k;
elseif p==-2.6
l=.0047*k;
elseif p==-2.7
l=.0033*k;
elseif p==-2.8
l=.0026*k;
elseif p==-2.9
l=.0018*k;
elseif p==-3.0
l=.0013*k;
else
l=0*k;
end
plot(t, p)
  1 Kommentar
Matt Fig
Matt Fig am 21 Nov. 2012
Bearbeitet: Matt Fig am 21 Nov. 2012
That code errors, so there is nothing to plot!
Also, you are not going to get the results you expect from that massive IF block. You are comparing floating points for equality, which is a bad idea. I also wonder if you are hoping the IF block will pick out each element of p one at a time... it won't.

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Walter Roberson
Walter Roberson am 21 Nov. 2012
Read the documentation on histc() and in particular pay attention to the multiple-output version of it.

Weitere Antworten (0)

Kategorien

Mehr zu 2-D and 3-D Plots finden Sie in Help Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by