slicing matrix in efficient way

I have a 120*1 matrix and i want to divide into 3 matrix x,y,z where first 10 elements goes to x, next 10 to y and next 10 to z and then next 10 elements to x as the second column. I did that

x = [1:10; 31:40; 61:70; 91:100] %=[10x4]
y = [11:20;41:50;71:80;101:.110] % =[10x4]
z= [21:30; 51:60; 81:90;111:120] %=[10x4]

Is there any efficient way to do that?

Answer 1

[Rik]

Something like this should do the trick:

a=1:120;
b=reshape(a,10,3,[]);

x=squeeze(b(:,1,:));
y=squeeze(b(:,2,:));
z=squeeze(b(:,3,:));

Answer 2

[madhan ravi]

Matrix = reshape(1:120,10,[]);
x = Matrix(:,1:3:end)
y = Matrix(:,2:3:end)
z = Matrix(:,3:3:end)

Answer 3

[James Tursa]

Another way:

a = 1:120;
r = reshape(a,30,[]);
x = r( 1:10,:);
y = r(11:20,:);
z = r(21:30,:);