Filter löschen
Filter löschen

Assigning or replacing elements of another array into an array based on indices

1 Ansicht (letzte 30 Tage)
I am trying to replace or assign elements into another array based on indices, I did it but only with only element, I can NOT replace or assign multiple elements
I am using index functions inclduing find but with multiple elements I can NOT.
clear all;
b = [0 0 45 -45 -45 45 90 90];
t_45_c=find(ismember(b,[45 -45]));
%b_new(t_90_c,t_0_c,t_45_c) = [8 9 2] % If I use this line I got an error of subscripted assignment dimension mismatch..
I want the b_new = [ 9 9 2 2 2 2 8 8]

Antworten (1)

Peter O
Peter O am 3 Jun. 2020
I suggest you use logical indexing for this instead of FIND. It's faster and a little cleaner.
Hope this helps!
b = [0 0 45 -45 -45 45 90 90];
% Assign each from a test condition.
% You can assign a scalar to multiple values at once.
b_new(b_new==90) = 8;
b_new(b_new==0) = 9;
b_new(abs(b_new)==45) = 2; % May have unexpected effects on complex qtys. Fine for real-valued.
b_new(b_new == 45 | b_new == -45) = 2; % This uses a compound OR operator to evaluate both +/-45 cases, or if you have two separate cases you want to match.
  1 Kommentar
Ali Tawfik
Ali Tawfik am 3 Jun. 2020
Thank you very much, I though I have to assign in one line multiple values,
I totally forgot that b_new is stored so the last b_new will be the result,

Melden Sie sich an, um zu kommentieren.


Mehr zu Matrix Indexing finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by