fsolve stopped because of relative size of current step
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I am trying to solve an equation using fsolve and I am getting the following error-
"fsolve stopped because the relative size of the current step is less than the
default value of the step size tolerance, but the vector of function values
is not near zero as measured by the default value of the function tolerance."
I am getting "No solution" even when I know that I should be getting a solution for all real values of psi. Can someone help me figure out what I need to change to get solutions.
syms y
psi = 0.1515;
r = 0.3;
a = r;
vf = [5 0];
m = 1;
x = linspace(-10*r,10*r);
x0 = ones(1,size(x,2));
opts = optimoptions(@fsolve,'Algorithm', 'levenberg-marquardt');
y = fsolve(@(y_val)solve_y(y_val,a,vf,x,psi,m),x0,opts);
% function solve_y
function F = solve_y(y_val,a,vf,x,psi,m)
y = y_val;
F = psi./norm(vf) - y - m*atan2(y,x+a) - m*atan2(y,x-a);
end
2 Kommentare
Alan Weiss
am 2 Jun. 2020
I'm not at all sure that I understand what you are doing. Are you trying to solve for a bunch of scalar roots all at once, or is your objective really vector-valued? Why do you have a syms y call at the start of your script?
Alan Weiss
MATLAB mathematical toolbox documentation
Antworten (1)
darova
am 14 Jun. 2020
use for loop
syms y
psi = 0.1515;
r = 0.3;
a = r;
vf = [5 0];
m = 1;
x = linspace(-10*r,10*r);
x0 = ones(1,size(x,2));
F = @(y,x) psi./norm(vf) - y - m*atan2(y,x+a) - m*atan2(y,x-a);
opts = optimoptions(@fsolve,'Algorithm', 'levenberg-marquardt');
for i = 1:length(x)
y0 = fsolve(@(y)F(y,x(i)),x(i));
line(x(i),y,'markerk','*')
end
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