getting index of elements

I have two vectors
g_vector = [2 0]
list = [3 0]
I would get the index of elements of g_vector that have their index in list matrix setted to 0. How can I do?
If I do
g_counter(list == 0)
I get 0 element of g_vector but I would have returned index 2 corresponding to the index of 0 in g_vector

Antworten (2)

Matt J
Matt J am 10 Nov. 2012

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find(list==0)

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Salvatore Mazzarino
Salvatore Mazzarino am 10 Nov. 2012
No it is not what I asked. The corresponding element of g_vector matrix has to be 0. In this way I don't know if the elements is 0 or not
Salvatore Mazzarino
Salvatore Mazzarino am 10 Nov. 2012
Bearbeitet: Salvatore Mazzarino am 10 Nov. 2012
What I mean is to create a way to do this
in list matrix we have 3 and 0. select index 2 of list matrix. Now I would get the index of g_vector that have index 2 and have also 0 as element
Salvatore Mazzarino
Salvatore Mazzarino am 10 Nov. 2012
Bearbeitet: Salvatore Mazzarino am 10 Nov. 2012
let me explain better
I have two vectors
g_counter = [2 0]
and
list = [3 0]
I would get the indices of all the elements belong to g_counter that have their position setted to zero and the corresponding position of list vector has to be setted to 0.
For instance with the given vectors I would get 2 as index. How can I do?
Matt J
Matt J am 10 Nov. 2012
find(g_counter==0 & list==0)

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Image Analyst
Image Analyst am 10 Nov. 2012

0 Stimmen

Perhaps one of these
index = find(g_counter == list(2))
index = find(g_counter == list(list==0))

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am 10 Nov. 2012

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