about random number and matrix
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
If I have only one random number rand(1) , R1 (1X N) and R2(1XN) are both vector of size N.
R1=a*[0:n-1];
R2=b*[0:n-1];
R2=rand(1)+R2; % add rand(1) to every element in R2
del=R1-R2' ; % "row vector-column vector" is interpreted as "matrix-matrix" with appropriate duplication of rows and columns
But i want to do monte carlo simulation so I need a lot of rand(1). For example rand(1000000,1). But i dont want to use any loops since it is unefficient.
How can I still do the two steps above ?
5 Kommentare
Walter Roberson
am 25 Mai 2020
That did not answer my question.
Your R1 is length n, and your R2 is length n as well, and you have 1000000 random numbers. What size of output of del do you want? n x n x 1000000 ? n x n x 1000000 x 1000000 ?
Antworten (1)
Walter Roberson
am 25 Mai 2020
Bearbeitet: Walter Roberson
am 25 Mai 2020
R1=a*[0:n-1];
R2=b*[0:n-1];
R2=rand(1, 1, 100000)+R2.'; % add rand to every element in R2
del=R1-R2 ; % "row vector-column vector" is interpreted as "matrix-matrix" with appropriate duplication of rows and columns
6 Kommentare
Walter Roberson
am 26 Mai 2020
Please re-check.
>> a = rand; b = rand; n = 5; R1=a*[0:n-1]; R2=b*[0:n-1]; R2=rand(1, 1, 100000)+R2.'; del=R1-R2 ;
>> size(del)
ans =
5 5 100000
Walter Roberson
am 26 Mai 2020
NB = 20; %number of bins
mind = min(del(:)); maxd = max(del(:));
bins = linspace(mind,maxd,NB); centers = mean([bins(1:end-1);bins(2:end)]);
counts = arrayfun(@(R,C) histcounts(del(R,C,:), bins), ndgrid(1:n,1:n), meshgrid(1:n,1:n), 'uniform', 0);
h = arrayfun(@(idx) bar(subplot(n,n,idx), centers, counts{idx}), 1:n^2);
Siehe auch
Kategorien
Mehr zu Creating and Concatenating Matrices finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!