keep element greater than immediate previous element

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Hi,
x = [1 2 3 4 3 2 3 4 6 8 5 5 6 8.5 9 11 12 ]; I want to keep one vector whereby the next element is greater than the immediate previous element. keep = [[1 2 3 4 6 8 8.5 9 11 12 ]; to discard if the element is smaller than or equal to the immediate previous element. discard = [3 2 3 4 5 5 6] (the bold elements in x).
I am using loop to do that and I didn't get what I want. could help modify my code or advise any alternative way? thanks in advance!
clc; clear; close all
x = [1 2 3 4 3 2 3 4 6 8 5 5 6 8.5 9 11 12 ];
m = length(x);
k=1; n = 1; i =1; j=2;
while i < m-1 & j < m
if x(j) >= x(i)
keep(n) = x(j);
n=n+1;
i=i+1;
j=j+1;
elseif x(j) < x(i)
discard(k) = x(j);
k = k+1;
i=i;
j=j+1;
end
end

Accepted Answer

Thiago Henrique Gomes Lobato
This loops does what you want:
x = [1 2 3 4 3 2 3 4 6 8 5 5 6 8.5 9 11 12 ];
m = length(x);
keep = [x(1)];
discard =[];
for idx=2:m
if x(idx)>keep(end)
keep = [keep,x(idx)];
else
discard = [discard,x(idx)];
end
end
keep
discard
keep =
1.0000 2.0000 3.0000 4.0000 6.0000 8.0000 8.5000 9.0000 11.0000 12.0000
discard =
3 2 3 4 5 5 6
Although, depending of your goal, simply sorting the array could solve the problem in a more simplified way:
keep = unique(sort(x))
keep =
1.0000 2.0000 3.0000 4.0000 5.0000 6.0000 8.0000 8.5000 9.0000 11.0000 12.0000
  2 Comments
Thiago Henrique Gomes Lobato
In mine matlab version it works fine, it can be that older versions have some problems with double indexing in cell array. One thing you could try is to remove the variables from the cell whenever possible until you get no error anymore, ex:
x1 = [1 2 3 4 3 2 3 4 6 8 5 5 6 8.5 9 11 12 ];
x2 = [1 2 3 4 3 2 3 4 6 8 5 5 6 8.5 9 11 12 ];
X = cell(2,1);
X{1} = x1;
X{2} = x2;
keep = cell(2,1);
for i = 1: length(X)
keep{i}(1) = [X{i}(1)];
actualX = X{i};
for idx = 2:length(actualX)
actualkeep = keep{i};
actualkeep = actualkeep(end);
if actualX(idx) > actualkeep
keep{i} = [keep{i},X{i}(idx)];
end
end
end
Although I would remain with the vectorized solution I suggested if all you want is the keep array

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More Answers (1)

per isakson
per isakson on 24 May 2020
An alternative
%%
x = [1 2 3 4 3 2 3 4 6 8 5 5 6 8.5 9 11 12 ];
%%
dx = 1;
while not( isempty( dx ) )
dx = find((diff(x)<=0));
x(dx+1)=[];
end
disp( x )
output
Columns 1 through 5
1 2 3 4 6
Columns 6 through 10
8 8.5 9 11 12
>>

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