In my problem, I have a car and multiple obstacle polyshape objects, and I want to determine if the car is overlapping only one of the obstacles. I found out that the `overlaps` command is very expensive, perhaps because it also checks if the obstacles overlap each other (a check that I don't need!)
if I do something like:
table = overlaps([car obstacle3 obstacle2])
I will get a matrix that shows me all of the possible overlaps with those 3 shapes.
I'm looking for a simple solution that will give me a true or false value - if the car object overlaps one of the obstacles (or more).
Thanks in advance!

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Matt J
Matt J am 16 Mai 2020
Bearbeitet: Matt J am 16 Mai 2020

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Use the two-argument form,
Obstacles=[obstacle3 obstacle2];
criterion = sum( overlaps(car,Obstacles) ) == 1 ; %true if one and only one obstacle intersected

1 Kommentar

Alon Osovsky
Alon Osovsky am 17 Mai 2020
Not exactly what I asked for, but I didn't know that there was a two-argument form. That helped - thanks a lot!

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