How can i use linspace with different intervals?

The value for x is 0 to 1. I want to use 0 to 0.9 with interval 0.01 and 0.9 to 1 with interval 0.99.

I used linspcae like this but this is giving me an error.

x = linspace(0,0.9,91;0.9,1,91);

How can i use different interval in linspace? Any idea?

Answer 1

[Rik]

You will have to call linspace multiple times:

part1=linspace(0,0.9,91);
part2=linspace(0.9,1,91);
x = [part1,part2(2:end)];

[Mahrosh]

thanks for your comments.

Answer 2

[Steven Lord]

If you know both endpoints and the interval, linspace isn't the best tool for the job. The colon operator (:) is.

x = 0:0.1:0.9;

Rik's suggestion of creating each piece independently and combining them afterwards, but use colon instead of linspace.

[Rik]

I had the same thought, but the interval sizes in the post itself didn't make sense to me. In hindsight I should have at least given it a mention, so thanks for the addition.

[Mahrosh]

Thanks steven for for your addition. For different interval can i define like this?

a = 0:0.01:0.9;
b = 0.9:0.001111111111111111:1;
x = [a,b(2:end)];

c=linspace(0,0.9,91);
d=linspace(0.9,1,91);
z = [c,d(2:end)];

If yes, then its giving me the same result as suggested by Rik.

[Steven Lord]

I probably have written the increment slightly differently for clarity:

b = 0.9:(1/900):1;

While there's still a magic number involved, I find they're often easier to understand and/or explain (depending on whether I'm reading or writing the code) when they're integer values (or the reciprocal of an integer value) than when they're some number written out to several decimal places.

[Mahrosh]

Thankyou steven for further explanation. I want to ask there is any effect on my calculation If I used number in decimal instead of intergers?

[Rik]

There isn't any difference in the result, only in how you read the code as a human.