Finding mean values several times.

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FV
FV am 7 Mai 2020
Beantwortet: Steven Lord am 7 Mai 2020
I want to find the mean of one part of a vector. I take the mean value of A1-5 , then A2-6, A3-7 and so on. I use this code: A(i)=mean(vector(i:i+4))
The problem is at the end of the vector. If its 10 A values I want the last average to go A5-10, A6-10, A7-10 and so on.
If it is a easy way to do this step several times I also want some help with this. So if 1=A1-5, 2=A2-6, 3=A3-7, I want to take average of 1-5, 2-6, 3-7 and so on.
I want to do this 4 or 5 times so I can find smothen out the values and find the peaks.
This was hard to describe, Hope you understand me.
  2 Kommentare
David Wilson
David Wilson am 7 Mai 2020
One option is to pad the end with enough NaNs, then use mean with the 'omitnan' flag, mean(..., 'omitnan')
ChrizzzlP
ChrizzzlP am 7 Mai 2020
You may want to look into the 'smooth' function, it sounds like what you're trying to do is smoothing a function and this will do it for you, there are several methods

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Antworten (2)

Paresh yeole
Paresh yeole am 7 Mai 2020
for i=1:n
if i+4<length(vector)
A(i) = mean(vector(i:i+4));
else
A(i) = mean(vector(i:end));
end
end
  2 Kommentare
FV
FV am 7 Mai 2020
This works for my first problem. Can I repeat this step several times without copying the whole thing?
Paresh yeole
Paresh yeole am 7 Mai 2020
Yes. You can.

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Steven Lord
Steven Lord am 7 Mai 2020
It sounds like the answer to the question you asked is movmean but you may not need to call movmean yourself.
Take a look at the smoothdata function to smooth your data and the islocalmax function to detect the local peaks. One of the options for how to smooth the data that smoothdata accepts is 'movmean'.

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