if... then... else?
6 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Hello,
I have the following problem:
- Assume a dataset [3000,1]
- We construct a variable ‘signal’, which will have the same size of our dataset. ‘signal’ will be either 1 or -1, based on the evolution of our dataset.
- At the starting point (1, 1), ‘signal’ will have the value 1. We keep this value until the dataset moves x % below its highest value during the time that ‘signal’ was equal to 1. From that moment on, the variable ‘signal’ will have the value -1.
- We keep this value until the dataset moves x % above its lowest value during the time that signal was equal to -1. From that moment on, the variable ‘signal’ will have the value 1 again.
- And so on, and so on...
- A short example may make my problem more clear:
x = 10%
- dataset / signal
- 97 / 1
- 100 / 1
- 93 / 1
- 89 / -1 / dataset moves x % below its highest value (100) during the '1' signal
- 86 / -1
- 80 / -1
- 93 / 1 / dataset moves x % above its lowest value (80) during the '-1' signal
- 94 / 1
- 95 / 1
- 92 / 1
- 80 -1 / dataset moves x % below its highest value (95) during the '1' signal
- … …
Can anybody help me with this issue?
Thanks
Pieter
1 Kommentar
Walter Roberson
am 11 Apr. 2011
I'm pretty sure you'll find an old cssm thread with exactly the same problem; see http://www.mathworks.com/matlabcentral/newsreader/
Akzeptierte Antwort
Oleg Komarov
am 11 Apr. 2011
Try this solution:
A = [97 100 93 89 86 80 93 94 95 92 80];
% Preallocate
Out = ones(size(A));
% First element is momentarily the maximum
maxA = A(1);
% Positive sequence
pos = true;
% Tolerance of 10%
x = .1;
% Start from the second element (since the first is considered the max)
for ii = 2:numel(A)
% 1
if pos
% If new maximum
if A(ii) > maxA
maxA = A(ii);
% If threshold is broken downwards
elseif A(ii)/maxA-1 < -x
minA = A(ii);
Out(ii) = -1;
pos = false;
end
% -1
else
Out(ii) = -1;
% If new minimum
if A(ii) < minA
minA = A(ii);
% If threshold is broken upwards
elseif A(ii)/minA-1 > x
maxA = A(ii);
Out(ii) = 1;
pos = true;
end
end
end
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Shifting and Sorting Matrices finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!