The velocity change of a motile is given as V(T)=T^3-6T^2+7 m/s.
calculate the acceleration at t= 3.5 seconds on matlab
to find the acceleration, I have to take the derivative of the given function and multiply it by 3.5.I find the derivative of the function, but I can't multiply it.

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Birdman
Birdman am 2 Mai 2020

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syms v(t)
v(t)=t.^3-6t.^2+7;
a(t)=diff(v);
result=a(3.5)

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