Confusion with interp3 and interpn
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Hi,
According to my teacher, "for a matrix indexed as [M, N, P], the axis variables must be given in the order N, M, P" in relation to the swaping of variables at the interp3 line:
[X, Y, Z] = size(data);
ts= [20 30 20]
[x, y, z] = ndgrid((1:X)/X, (1:Y)/Y, (1:Z)/Z);
[x2, y2, z2] = ndgrid((1:ts(1))/(ts(1)), (1:ts(2))/(ts(2)), (1:ts(3))/(ts(3)));
test1= interp3(y, x, z, data, y2, x2, z2, 'linear');
However, I couldn't find this info on the function's page, nor it makes any sense to me (even though the computation seems correct!).
Any help welcome, thank you,
TS
5 Kommentare
darova
am 24 Apr. 2020
I don't understand the question. What are you asking?
Tahariet Sharon
am 26 Apr. 2020
darova
am 25 Mai 2020
Did you try 'x,y,z' order? I think the result should be the same
Tahariet Sharon
am 25 Mai 2020
Bearbeitet: Tahariet Sharon
am 25 Mai 2020
darova
am 25 Mai 2020
Maybe it's the answer on your question
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darova
am 25 Mai 2020
here is an example
[x,y] = meshgrid(1:5);
z = x.^2 + y.^2/2;
[x1,y1] = meshgrid(1:0.5:5);
z1 = interp2(x,y,z,x1,y1); % standart interpolation
z2 = interp2(y',x',z,y1',x1'); % interpolation y x
surf(x,y,z,'facecolor','none')
hold on
plot3(x1(:),y1(:),z1(:),'.r')
plot3(x1(:),y1(:),z2(:),'ob')
hold off
legend('original surface',...
'standard interpolation',...
'y x interpolation','location','north')
axis vis3d

2 Kommentare
Tahariet Sharon
am 26 Mai 2020
Tahariet Sharon
am 26 Mai 2020
Bearbeitet: Tahariet Sharon
am 26 Mai 2020
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