How to list files with multiple extensions?

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Kevin
Kevin am 24 Okt. 2012
Bearbeitet: Cris LaPierre am 9 Jan. 2024
Suppose I want mp3 or avi files from a folder, on Unix I could do
ls *.{mp3|avi}
Is there a clean one-liner way to do this in matlab? Presently, I can do it in two lines by doing the following:
f = dir(folder)
f(~cellfun(@isempty,regexpi({f.name},'.*(mp3|avi)'))).name
However, I find this rather ugly compared to the simplicity of the first expression.
Thanks, Kevin
  1 Kommentar
Matt J
Matt J am 24 Okt. 2012
Bearbeitet: Matt J am 24 Okt. 2012
If you find it ugly, why not just wrap it in an mfile of your own?

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Antworten (3)

Doug Hull
Doug Hull am 24 Okt. 2012
Can you run the command twice with two filters? The results would be two structures of the same format that could then be appended together.
  2 Kommentare
Kevin
Kevin am 24 Okt. 2012
Specifically, do you mean something like this?
f = [dir(fullfile(folder,'*mp3')); dir(fullfile(folder,'*avi'))];
I considered this, and it can certainly do for my present situation. However, it doesn't scale as well to more than a couple of extensions (at least the way I presented it) as the cellfun thing I put previously.
Thanks for the suggestion, though!
Sean de Wolski
Sean de Wolski am 24 Okt. 2012
@Kevin, a for-loop over a cell array containing the extentions would allow it to scale, though concatenating structures is ugly.

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Sean de Wolski
Sean de Wolski am 24 Okt. 2012
You could just farm that command out to Unix if you are on a unix system...
  1 Kommentar
Kevin
Kevin am 24 Okt. 2012
You mean, something like:
[~, sysout] = system(['ls ' fullfile(folder,'*{mp3,avi}')]);
fileNames = regexp(sysout,'\n','split');
While this would work, cross comparability with windows is a must for me. Thanks for your input, though!

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ANKUR WADHWA
ANKUR WADHWA am 6 Nov. 2019
Bearbeitet: Cris LaPierre am 9 Jan. 2024
Though the thread is very old still for users who are looking for an easy way a very simple existing solution on Matlbcentral

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