Code is stuck in infinite loop

5 Ansichten (letzte 30 Tage)
haif hamza
haif hamza am 14 Apr. 2020
Kommentiert: haif hamza am 15 Apr. 2020
Trying to find to roots of the function in my code using the incremental search method, but it looks like the code is stuck looping in one condition.
dx=0.1; epsi=0.01; Xi=0.1; Xm=4.0;
F = @(x) 1+5.25*x-sec(sqrt(0.68*x));
a=Xi;
f1=F(a);
b=a+dx;
f2=F(b);
while a<Xm
a=Xi;
f1=F(a);
b=a+dx;
f2=F(b);
if abs(f2) > (1/epsi)
disp ('function approaching infinity at ',a);
a = a+epsi;
f1=F(a);
b=a+dx;
f2=F(b);
else
if f1*f2 == 0
disp ('X is a root',a);
a = a+epsi;
f1=F(a);
b=a+dx;
f2=F(b);
elseif f1*f2 > 0
if a>Xm
break;
else
a=b;
f1=F(a);
b=a+dx;
f2=F(b);
end
else
if dx < epsi
disp ('X is a root',a);
a = a+epsi;
f1=F(a);
b=a+dx;
f2=F(b);
else
a=a-dx;
dx = dx/10;
f1=F(a);
b=a+dx;
f2=F(b);
end
end
end
end

Antworten (1)

Geoff Hayes
Geoff Hayes am 14 Apr. 2020
haif - part of the problem (of why you are getting stuck in an infinite loop) is due to
dx=0.1;
epsi=0.01;
Xi=0.1; % <----- set here only
Xm=4.0;
F = @(x) 1+5.25*x-sec(sqrt(0.68*x));
a=Xi; % <------ a initialized to Xi
f1=F(a);
b=a+dx;
f2=F(a)
while a<Xm
a=Xi; % <------ a reset to static Xi
On each iteration of the loop, the code is always re-assigning a to Xi and since the latter is only set outside the loop, then we are always repeating the same iteration again and again. Try commenting out this line and re-running your code. You'll probably also have a problem with
disp ('function approaching infinity at ',a);
with a "too many input arguments" error. Just change this to
disp (sprintf('function approaching infinity at %f',a));
  1 Kommentar
haif hamza
haif hamza am 15 Apr. 2020
Thank you, your solution worked. For the second problem i used fprintf

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by