ezplot('((5.14*10^(-4))-(6.44*10^(-5)*i))*exp(5*i*t)+exp(-0.796*t)*(0.99+6.44*10^(-5)*i)*cos(7.96*t)+exp(-0.796*t)*(-0.099-3.29*10^(-4)*i)*sin(7.96*t)',[0,20])
nothing appears when i use ezplot i dont know why

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Ameer Hamza
Ameer Hamza am 11 Apr. 2020
Bearbeitet: Ameer Hamza am 11 Apr. 2020

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You equation returns numbers with both real and imaginary parts. Following code plots both
f = @(t) ((5.14*10^(-4))-(6.44*10^(-5)*1i)).*exp(5*1i*t)+exp(-0.796*t).*(0.99+6.44*10^(-5)*1i).*cos(7.96*t)+exp(-0.796*t).*(-0.099-3.29*10^(-4)*1i).*sin(7.96*t);
t = linspace(0,20,1000);
f_value = f(t);
subplot(2,1,1);
plot(t, real(f_value))
title('real');
subplot(2,1,2);
plot(t, imag(f_value))
title('imaginary');

2 Kommentare

Seungwon Lee
Seungwon Lee am 12 Apr. 2020
thanks for answering Ameer Hamza. Can you tell me the meaning of @(t) in the fist line?
Ameer Hamza
Ameer Hamza am 12 Apr. 2020
This is a way to define an anonymous function. It is used to define simple functions without using a function block. If you have experience with other programming languages, then you can think of its as a lambda function.

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Geoff Hayes
Geoff Hayes am 11 Apr. 2020

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Seungwon - try using fplot instead which is recommended to be used instead of ezplot. Note that when I run your code with ezplot, nothing shows up for me either....yet it does work with fplot.

1 Kommentar

Seungwon Lee
Seungwon Lee am 12 Apr. 2020
Sorry but nothing appears eventhough i changed ezplot to fplot. Does it work on yours?

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