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write a function called tri_area returns the area of a triangle with base b and height h

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Andrew Ayman
Andrew Ayman on 9 Apr 2020
Answered: Eshan Pansare on 28 Aug 2020
hello this is my function code and command window code and there is a message of invalid expression at line 2 and i dont know what is the wrong can anyone help me
function [area] = tri_area([b,h]);
tri_area([b,h])=(0.5)*(b)*(h)
area=tri_area([b,h])
end
%command window
area = tri_area[3,2])

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Walter Roberson
Walter Roberson on 10 Aug 2020
Assuming that Nur Ameera Nabila Abdul Rahim is addressing Naveen Gehlot then:
area=(1/2)*(b)*(h)
is just the standard formula for the area of a triangle.
vca = area(:);
tri_area = sum(vca);
That is one way of calculating the total area, which is something that might potentially be done if the user asked to calculate the area for multiple triangles at the same time. However, if the user did ask to calculate for multiple triangles at the same time, it is fairly likely that area=(1/2)*(b)*(h) would be the wrong formula, and that it should instead be
area=(1/2)*(b).*(h);
or better
area = (1/2) .* b(:) .* h(:);
Christine Mizzi
Christine Mizzi on 27 Aug 2020
What is the purpose for writing two output arguments in the code? i.e. [area, tri_area]
If the user is calling the area of a triangle wouldn't that be only one output argument?

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Accepted Answer

Torsten
Torsten on 9 Apr 2020
Edited: darova on 9 Apr 2020
function area = tri_area(b,h)
area = 0.5*b*h;
end
From the command window
A = tri_area(3,2)

  17 Comments

Walter Roberson
Walter Roberson on 10 Aug 2020
Have you considered adding disp statements so you can see what parameters are being passed for the random input case?

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More Answers (2)

Ramakant Gupta
Ramakant Gupta on 15 May 2020
Edited: Walter Roberson on 2 Jun 2020
function area = tri_area(b,h)
area = 0.5*b*h;
end

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