How to make a bode plot from a transfer function
141 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Uzair Akhtar
am 9 Apr. 2020
Kommentiert: Star Strider
am 9 Apr. 2020
Hi how would I make a blode plot from this transfer function?
Gp(s) = (10e^-0.25S)/((1+1.2S)(1+3.5S))
is this the correct code in Matlab?
0 Kommentare
Akzeptierte Antwort
Star Strider
am 9 Apr. 2020
Yes.
The code you posted:
s = tf('s');
g = 10*exp(-0.25*s)/((1+1.2*s)*(1+3.5*s))
figure
bode(g)
grid
should work.
Are you having problems with it?
4 Kommentare
Star Strider
am 9 Apr. 2020
As always, my pleasure!
It looks correct to me. Note that the exponential term is an output delay that primarily affects the phase of the Bode plot.
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Plot Customization finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!