Getting a warning when I fplot

Im getting the correct graph and everything is running correctly, but I keep getting this warning after I fplot. How can I fix it?

Antworten (1)

Walter Roberson
Walter Roberson am 9 Apr. 2020
Bearbeitet: Walter Roberson am 9 Apr. 2020

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fplot passes a vector of values into the function, so in C, T will be a vector of values. But you are using T as the upper bound on integral(), but integral() can only have a single upper bound.
You need to do something like
C = @(t) arrayfun(@(T) H+(S(1)/S(2))*integral(A,25,T)+(S(3)/S(4))*integral(B,25,T), t);
However, I would recommend that you just be smarter about your integrals. The integral of D1+D2*T+D3*T^2 for T from P to Q is (D1*Q + D2/2*Q.^2 + D3/3*Q.^3) - (D1*P + D2/2*P.^2 + D3/3*P.^3) . That is something that you can easily vectorize, so your C can be calculated without any integral() calls, and so could be vectorized for use with fplot()

1 Kommentar

Walter Roberson
Walter Roberson am 9 Apr. 2020
Note by the way that you could use https://www.mathworks.com/help/matlab/ref/polyint.html together with polyval() instead of integral() . polyval has the advantage of being vectorized.

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