Getting a warning when I fplot

3 Ansichten (letzte 30 Tage)
Jose Grimaldo
Jose Grimaldo am 8 Apr. 2020
Kommentiert: Walter Roberson am 9 Apr. 2020
Im getting the correct graph and everything is running correctly, but I keep getting this warning after I fplot. How can I fix it?

Antworten (1)

Walter Roberson
Walter Roberson am 9 Apr. 2020
Bearbeitet: Walter Roberson am 9 Apr. 2020
fplot passes a vector of values into the function, so in C, T will be a vector of values. But you are using T as the upper bound on integral(), but integral() can only have a single upper bound.
You need to do something like
C = @(t) arrayfun(@(T) H+(S(1)/S(2))*integral(A,25,T)+(S(3)/S(4))*integral(B,25,T), t);
However, I would recommend that you just be smarter about your integrals. The integral of D1+D2*T+D3*T^2 for T from P to Q is (D1*Q + D2/2*Q.^2 + D3/3*Q.^3) - (D1*P + D2/2*P.^2 + D3/3*P.^3) . That is something that you can easily vectorize, so your C can be calculated without any integral() calls, and so could be vectorized for use with fplot()
  1 Kommentar
Walter Roberson
Walter Roberson am 9 Apr. 2020
Note by the way that you could use https://www.mathworks.com/help/matlab/ref/polyint.html together with polyval() instead of integral() . polyval has the advantage of being vectorized.

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu MATLAB finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by