How do I create a source field of light through a circular aperture?
6 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Janna Hinchliff
am 8 Apr. 2020
Beantwortet: darova
am 8 Apr. 2020
I have been trying to construct a code where I propagate a light source through a circular aperture. So far I have
L1=0.5; % side length
M=500; % number of samples
dx1=L1/M; % src sample interval
x1=-L1/2:dx1:L1/2-dx1; % src coords
y1=x1;
lambda=500*10^-9; % wavelength
k=2*pi/lambda; % wavenumber
w=0.05; % source half width (m)
z=500; % propagation dist and focal length (m)
[X1,Y1]=meshgrid(x1,x1);
u1=circ(sqrt(X1^2+Y1^2)/w); % src field
I1=abs(u1.^2); % src intensity
figure;
imagesc(x1,y1,I1);
axis square; axis xy;
colormap('gray'); xlabel('x (m)'); ylabel('y (m)');
title('z= 0 m');
but the intensity plot shown does not represent a circular source. Is my definition of u1 incorrect or have a made an error in the coding?
I have defined the function circ as
function[out]=circ(r)
%
% circle function
%
% evaluates circ(r)
% note: returns odd number of samples for diameter
%
out=abs(r)<=1;
end
0 Kommentare
Akzeptierte Antwort
darova
am 8 Apr. 2020
First of all you forgout about element-wise:
X1.^2 + Y.^2 % each element of matrix in power '2'
Here is what i tried
0 Kommentare
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Image Processing Toolbox finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!