Print out a one column array

I have written the code below and it successfully prints out the average that I want PTS/G for all 20 values, however the matrix that is printed out has 19 extra columns of 0s. How do I delete those?

%average points per season 
%ave = (PTS/G) 
PTS =[539;1220;996;1485;1938;2019;2461;1557;1819;2832;2430;2323;2201;1970;2078;1616;2133;83;782;1161]
G = [71;79;50;66;68;80;82;65;66;80;77;82;82;73;82;58;78;6;35;66]
for ii=1:20
    ave(ii)= PTS(ii)/G(ii)
    disp(PTS(ii)/G(ii))
end

Answer 1

[Tommy]

The extra columns may be left over from running

ave = (PTS/G)

If you clear your workspace, they should go away. However, if you want to divide each value in PTS by the corresponding value in G, you can just use

ave = PTS./G

[collegestudent]

And if I want to add the calculated ave values to have a year appear beside them increasing each time, how would I do that?

[Tommy]

Do you mean something like this?

PTS = [539;1220;996;1485;1938;2019;2461;1557;1819;2832;2430;2323;2201;1970;2078;1616;2133;83;782;1161];
G = [71;79;50;66;68;80;82;65;66;80;77;82;82;73;82;58;78;6;35;66];
ave = PTS./G;
yrs = (2000:2019)';
fprintf('%.2f avg points per game in %i\n', [ave yrs]')

[collegestudent]

Yes! Exactly that, but including the for loop from before. Is that possible?

[Tommy]

Sure, maybe this?

PTS = [539;1220;996;1485;1938;2019;2461;1557;1819;2832;2430;2323;2201;1970;2078;1616;2133;83;782;1161];
G = [71;79;50;66;68;80;82;65;66;80;77;82;82;73;82;58;78;6;35;66];
yrs = (2000:2019)';
for ii = 1:numel(PTS)
    fprintf('%.2f avg points per game in %i\n', PTS(ii)/G(ii), yrs(ii))
end

If these are soccer games, I'm impressed!

[collegestudent]

This worked great thank you so much for getting back to me so quicky! No I wish it was soccer, it is Kobe's stats through his seasons :)

[Tommy]

Ah :'(

But happy to help!