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undefined function 'f'

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Titas Chattopadhyay
Titas Chattopadhyay am 31 Mär. 2020
Kommentiert: Ameer Hamza am 31 Mär. 2020
tmesh = linspace(0,pi/2,5);
solinit = bvpinit(tmesh, @f);
sol = bvp4c(@odefun, @bcfun, solinit);
plot(sol.x, sol.y, '-o');
FUNCTION
function dzdt = odefun(t,z)
dzdt = zeros(2,1);
dzdt = [z(2)+z(1)];
end
% boundary conditions
function res = bcfun(za, zb)
res = [za(1) zb(pi/2)-2]
end
% Initial guess
function g = f(t)
g = [sin(t) cos(t)];
end
error unrecognized function or variable 'f'
  3 Kommentare
Walter Roberson
Walter Roberson am 31 Mär. 2020
If you stored those three functions together in one file, and had the script in another file, then the script would only be able to see the first function inside the file of functions. Only the first function in a file of functions is visible to the outside normally; the rest are private implementations only for use by that function (typically)
Titas Chattopadhyay
Titas Chattopadhyay am 31 Mär. 2020
So, I have to make 3 function files for func ,bcs and ics. Right?

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Ameer Hamza
Ameer Hamza am 31 Mär. 2020
Bearbeitet: Ameer Hamza am 31 Mär. 2020
Either write all the functions in one file like this. (Also note that I have made few changes in your code.)
tmesh = linspace(0,pi/2,5);
solinit = bvpinit(tmesh, @f);
sol = bvp4c(@odefun, @bcfun, solinit);
plot(sol.x, sol.y, '-o');
function dzdt = odefun(t,z)
dzdt = zeros(2,1);
dzdt = [z(2); z(1)]; % <----- This should be a 2x1 vector
end
% boundary conditions
function res = bcfun(za, zb)
res = [za(1); zb(2)-2]; % <---- boundary conditions are written like this, zb(pi/2) is invalid
end
% Initial guess
function g = f(t)
g = [sin(t) cos(t)];
end
Or create 4 files like this.
main_script:
tmesh = linspace(0,pi/2,5);
solinit = bvpinit(tmesh, @f);
sol = bvp4c(@odefun, @bcfun, solinit);
plot(sol.x, sol.y, '-o');
odefun.m:
function dzdt = odefun(t,z)
dzdt = zeros(2,1);
dzdt = [z(2); z(1)];
end
bcfun.m:
% boundary conditions
function res = bcfun(za, zb)
res = [za(1); zb(2)-2];
end
f.m:
% Initial guess
function g = f(t)
g = [sin(t) cos(t)];
end
  2 Kommentare
Titas Chattopadhyay
Titas Chattopadhyay am 31 Mär. 2020
Thank you so much.
Ameer Hamza
Ameer Hamza am 31 Mär. 2020
Glad to be of help.

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