Fitting to an intergral

2 Ansichten (letzte 30 Tage)
Jason Ngo
Jason Ngo am 27 Mär. 2020
Beantwortet: Torsten am 27 Mär. 2020
I am trying to fit a set of data to an integral with the following code but I get an error message. The parameters I am trying to obtain is x(1),x(2), and u, from xdata and ydata. Thanks.
fun= @(x, xdata) (1-((6*x(1))/(pi*sqrt(x(2)))))*integral(@(u) ((exp(-(xdata))*((u*cos(u)-sin(u))^2))/((u^2)*(((u^2)*(sin(u))^2)+(x(2))*(((x(1))/(x(2)))*(u*cos(u)-sin(u))+sin(u))^2))),0,Inf)
x0=(1,1)
lsqcurvefit(fun, x0, xdata, ydata)
Error using *
Incorrect dimensions for matrix multiplication. Check that the number of columns in the first matrix matches the number of rows in the second matrix.
To perform elementwise multiplication, use '.*'.
Error in @(u)((exp(-(xdata))*((u*cos(u)-sin(u))^2))/((u^2)*(((u^2)*(sin(u))^2)+(x(2))*(((x(1))/(x(2)))*(u*cos(u)-sin(u))+sin(u))^2)))
Error in integralCalc/iterateScalarValued (line 314)
fx = FUN(t);
Error in integralCalc/vadapt (line 132)
[q,errbnd] = iterateScalarValued(u,tinterval,pathlen);
Error in integralCalc (line 83)
[q,errbnd] = vadapt(@AToInfInvTransform,interval);
Error in integral (line 88)
Q = integralCalc(fun,a,b,opstruct);
Error in
@(x,xdata)(1-((6*x(1))/(pi*sqrt(x(2)))))*integral(@(u)((exp(-(xdata))*((u*cos(u)-sin(u))^2))/((u^2)*(((u^2)*(sin(u))^2)+(x(2))*(((x(1))/(x(2)))*(u*cos(u)-sin(u))+sin(u))^2))),0,Inf)
Error in lsqcurvefit (line 213)
initVals.F = feval(funfcn_x_xdata{3},xCurrent,XDATA,varargin{:});
Caused by:
Failure in initial objective function evaluation. LSQCURVEFIT cannot continue.

Akzeptierte Antwort

Torsten
Torsten am 27 Mär. 2020
Use "ArrayValued=true" as option in the call to integral.

Weitere Antworten (0)

Kategorien

Mehr zu Get Started with Curve Fitting Toolbox finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by