Aiming to solve function and have one of the variables be a minimum value:
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Samy Abisaleh
am 26 Mär. 2020
Kommentiert: Samy Abisaleh
am 27 Mär. 2020
syms r x
a = 100;
Cp = .70;
b = .50206;
c = 67.402;
d = 1.2;
e = .0277777778;
eqn = ((100*Cp*x)-(b*x*r*r))/((100*Cp*x)-(c/r)-(b*x*r*r)) == exp(d*acos(e*r));
solx = solve(eqn, x)
[r, fval] = fminsearch(matlabFunction(solx),[1 1])
So I know the last part is wrong. But I am given the "eqn" and I want X to be a minimum value. I am not sure which matlab method I should use to make this happen. I tried to use fminsearch, but it refuses to solve it that way, and I was wondering if theres another method I am unaware of. The r value can be variable and what it ends up being isn't important to me.
Thanks!
0 Kommentare
Akzeptierte Antwort
Birdman
am 27 Mär. 2020
The key point here is to define solx as a function of r. Try the following code:
syms r x
a = 100;
Cp = .70;
b = .50206;
c = 67.402;
d = 1.2;
e = .0277777778;
eqn = ((100*Cp*x)-(b*x*r*r))/((100*Cp*x)-(c/r)-(b*x*r*r)) == exp(d*acos(e*r));
solx(r) = solve(eqn, x)
[r, fval] = fminsearch(matlabFunction(solx),1)
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Logical finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!