Info
Diese Frage ist geschlossen. Öffnen Sie sie erneut, um sie zu bearbeiten oder zu beantworten.
Read spesific rowintervals from .txt file and store them
    2 Ansichten (letzte 30 Tage)
  
       Ältere Kommentare anzeigen
    
I am trying to read a large .txt doc that continues for maany rows. I have tried to do it manually by the following code:
for i = 12
    C = textscan(fid,'%.6f %.6f',npoints,'delimiter','\n', 'headerlines',i-1);
    p1 = C{1}*1e3;
    y1 = C{2};
    py1 = [p1 y1];
end
for i = 40
    C = textscan(fid,'%.6f %.6f',npoints,'delimiter','\n', 'headerlines',i-1);
    p2 = C{1}*1e3;
    y2 = C{2};
    py2 = [p2 y2];
end
for i = 68
    C = textscan(fid,'%.6f %.6f',npoints,'delimiter','\n', 'headerlines',i-1);
    p3 = C{1}*1e3;
    y3 = C{2};
    py3 = [p3 y3];
end
Is it possible to do this is one loop ? the number of rows are equal for all the "intervals" such that "npoints" is fixed 21. and it is 28 spaces between each interval so I was thinking something like for i = [12:28:1356] where 1356-1376 is the last interval.
0 Kommentare
Antworten (1)
  KSSV
      
      
 am 25 Mär. 2020
        I = [12 40 68] ; 
iwant = cell(length(I),1) ; 
for i = 1:length(I)
    C = textscan(fid,'%.6f %.6f',npoints,'delimiter','\n', 'headerlines',I(i)-1);
    p1 = C{1}*1e3;
    y1 = C{2};
    py1 = [p1 y1];
    iwant{i} = py1 ; 
end
4 Kommentare
Diese Frage ist geschlossen.
Siehe auch
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
