I have a column of data with rainfall on each day, from 2004 to 2016. I want to be able to extract the rainfall data for each day and store that data into columns of months for each year. I have created a loop that finds the end day of all months from 2004 to 2016, but am having trouble now extracting the information.
[SL: formatted question as text not code]

2 Kommentare

Mohammad Sami
Mohammad Sami am 24 Mär. 2020
Bearbeitet: Mohammad Sami am 24 Mär. 2020
Create a vector to store the index of the days (rows) you want to extract. Then you can simply subset.
Asanka Subasinghe
Asanka Subasinghe am 24 Mär. 2020
I need some sort of loop because theres more than 4000 data points

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Walter Roberson
Walter Roberson am 24 Mär. 2020
Bearbeitet: Walter Roberson am 24 Mär. 2020

0 Stimmen

Dv = Dates(:) ;
Output = accumarray([day(Dv), month(Dv), year(Dv)-2003], Rainfall(:), [31 12 13], [], nan);
The result will be a 3d array with one pane for each year, with rows being day numbers, columns being month numbers. Unused entries such as shorter months or missing data will be set to nan

6 Kommentare

Asanka Subasinghe
Asanka Subasinghe am 25 Mär. 2020
I am receiving an error message that says
Error using accumarray
First input SUBS and third input SZ must satisfy
ALL(MAX(SUBS)<=SZ).
Can you please explain what each input of accumarray does?
Thanks
current code is :
clc;clear all;close all
filename='Data Q2 (2).xlsx';
[num,txt,raw]=xlsread(filename);
dandenongdate=txt(2:end,1);
dandenongnum=num(:,1);
Dv = dandenongdate ;
Output = accumarray([day(Dv), month(Dv), year(Dv)-2003], dandenongnum, [31 12 13], [], nan);
Walter Roberson
Walter Roberson am 25 Mär. 2020
Use readtable so that you get datetime objects not date vectors.
Asanka Subasinghe
Asanka Subasinghe am 25 Mär. 2020
It tells me Error using day (line 37)
You cannot subscript a table using linear indexing (one
subscript) or multidimensional indexing (three or more
subscripts). Use a row subscript and a variable subscript.
What does it mean by row and variable subscript?
Thank you
clc;clear all;close all
filename='Data Q2 (2).xlsx';
data=(readtable(filename))
dandenongnum=data(:,2);
dandenongdate=data(:,1);
Dv=dandenongdate;
Output = accumarray([day(Dv), month(Dv), year(Dv)-2003], dandenongnum, [31 12 13], [], nan);
clc;clear all;close all
filename='Data Q2 (2).xlsx';
data=(readtable(filename))
dandenongnum=data{:,2};
dandenongdate=data{:,1};
Dv=dandenongdate;
Output = accumarray([day(Dv), month(Dv), year(Dv)-2003], dandenongnum, [31 12 13], [], nan);

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am 24 Mär. 2020

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