pzplot in symbolic toolbox
15 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Hi, I'm using following command to achieve tf of Y_out.
for l=1:4
[symNum,symDen] = numden(Y_out(1,l)); %Get num and den of Symbolic TF
TFnum = sym2poly(symNum); %Convert Symbolic num to polynomial
TFden = sym2poly(symDen); %Convert Symbolic den to polynomial
sys =tf(TFnum,TFden);
pzplot(sys)
end
as you can see Y_out has 1 row and 4 column.
how can I PZPLOT the sys(1),...,sys(4) all in a same plot or different plots?
thx
0 Kommentare
Antworten (1)
Star Strider
am 21 Mär. 2020
‘as you can see Y_out has 1 row and 4 column.’
We cannot see any of that because they are not provided.
This could work, although I cannot even test it or simulate it because I do not know what ‘Y_out’ is:
for l=1:4
[symNum,symDen] = numden(Y_out(1,l)); %Get num and den of Symbolic TF
TFnum = sym2poly(symNum); %Convert Symbolic num to polynomial
TFden = sym2poly(symDen); %Convert Symbolic den to polynomial
sys =tf(TFnum,TFden);
figure
pzplot(sys)
end
0 Kommentare
Siehe auch
Kategorien
Mehr zu Linear Algebra finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!