Taylor Series of e^x

The program calculates e^x by adding terms of the series and stopping when the absolute value of the term that was added last is smaller than 0.0001. Use a while-end loop, but limit the number of passes to 30. If in the 30th pass the value of the term that is added is not smaller than 0.0001, the program stops and displays a message that more than 30 terms are needed.

clear
clc
fprintf('Solving e^x using Taylor Series\n');
x=input('x = ');
n=30; 
i=0;
f=1;
while i<n || i==n
    f=f+(x.^i)/factorial(i);
    i=i+1;
end
y=f-1

This is where I am stuck, I don't know how to limit the n to 30 and how can I make a condition that if the value of the term is smaller than 0.0001 it will stop.

Any help would be appreciated, Thank you!

[Walter Roberson]

while term is in range && iterations is in range 
  Calculate a term
  accumulate term into total 
  increment iterations

Answer 1

[Subhamoy Saha]

clear
clc
fprintf('Solving e^x using Taylor Series\n');
x=input('x = ');
n=30; 
i=0;
f=1;
while i<=n
    last_term=(x.^i)/factorial(i);
    if (x.^i)/factorial(i)<0.0001
        msgbox('Last term is smaller than 0.0001 and hence stopped')
        break
    elseif i==n && last_term>0.0001
        msgbox('More steps needed')
        break
    end
    f=f+last_term;
    i=i+1;
end
y=f-1

[Joseph Melo Manalo]

Thank you so much. I learned again today.

[Walter Roberson]

We recommend against providing complete solutions to homework questions.

[Subhamoy Saha]

I didn't realised that @Walter.

[Joseph Melo Manalo]

I just read the rules in asking homework and I am really sorry for not tagging "homework". I thank you both also for answering my questions. I have learn that I can learn better using actual example, so even though Subhamoy Saha didn't exactly write the code that I need. I can work from there. Again I am sorry and Thank you both!

Answer 2

[Mohamed Hakim]

function [ts]=newton(x,n)
  i=1;
  ts=1;
  
  while i<n || i==n
      ts=ts+(x.^i)/factorial(i);
      i=1+i;
  end
end

[Walter Roberson]

Is there a reason to write

i<n || i==n

instead of

i<=n

?

Answer 3

[Mohamed Hakim]

y= @(x) 2*x^2-5*x+3;
x1=input("enterfirst number");
x2=input("enterfirst number");
if f(x1)*f(x2)==0
    disp("no");
end