Filter löschen
Filter löschen

Vectorization, avoiding loops

3 Ansichten (letzte 30 Tage)
Jarl Bergström
Jarl Bergström am 11 Mär. 2020
Kommentiert: Jarl Bergström am 14 Mär. 2020
Hello!
I have a Matrix, A=rand(9,10)
Now, I want to add a new number, to a new row, for every column b=[2,3,4;7 1 6];
I can do this using loops but I want to use Vectorization for speed.
A ( end +1 , b(1) ) = 1
A ( end +1 , b(2) ) = 1
A ( end +1 , b(3) ) = 1
Thank you :)

Akzeptierte Antwort

tmarske
tmarske am 11 Mär. 2020
Assuming this:
b=[2,3,4;7 1 6];
is a typo and supposed to read:
b=[2,3,4,7,1,6];
Then you can make the new rows as a matrix of zeros, set appropriate elements = 1, then concatenate:
A = rand(9, 10)
b=[2,3,4,7,1,6];
%make the new rows as a single block
newRows = zeros(length(b), size(A, 2));
bIx = sub2ind(size(newRows), 1:length(b), b);
newRows(bIx) = 1;
%concatenate them
A = [A; newRows]
Example output:
A =
0.5470 0.0811 0.8176 0.5502 0.2259 0.9797 0.2217 0.0292 0.5211 0.8852
0.2963 0.9294 0.7948 0.6225 0.1707 0.4389 0.1174 0.9289 0.2316 0.9133
0.7447 0.7757 0.6443 0.5870 0.2277 0.1111 0.2967 0.7303 0.4889 0.7962
0.1890 0.4868 0.3786 0.2077 0.4357 0.2581 0.3188 0.4886 0.6241 0.0987
0.6868 0.4359 0.8116 0.3012 0.3111 0.4087 0.4242 0.5785 0.6791 0.2619
0.1835 0.4468 0.5328 0.4709 0.9234 0.5949 0.5079 0.2373 0.3955 0.3354
0.3685 0.3063 0.3507 0.2305 0.4302 0.2622 0.0855 0.4588 0.3674 0.6797
0.6256 0.5085 0.9390 0.8443 0.1848 0.6028 0.2625 0.9631 0.9880 0.1366
0.7802 0.5108 0.8759 0.1948 0.9049 0.7112 0.8010 0.5468 0.0377 0.7212
A =
0.5470 0.0811 0.8176 0.5502 0.2259 0.9797 0.2217 0.0292 0.5211 0.8852
0.2963 0.9294 0.7948 0.6225 0.1707 0.4389 0.1174 0.9289 0.2316 0.9133
0.7447 0.7757 0.6443 0.5870 0.2277 0.1111 0.2967 0.7303 0.4889 0.7962
0.1890 0.4868 0.3786 0.2077 0.4357 0.2581 0.3188 0.4886 0.6241 0.0987
0.6868 0.4359 0.8116 0.3012 0.3111 0.4087 0.4242 0.5785 0.6791 0.2619
0.1835 0.4468 0.5328 0.4709 0.9234 0.5949 0.5079 0.2373 0.3955 0.3354
0.3685 0.3063 0.3507 0.2305 0.4302 0.2622 0.0855 0.4588 0.3674 0.6797
0.6256 0.5085 0.9390 0.8443 0.1848 0.6028 0.2625 0.9631 0.9880 0.1366
0.7802 0.5108 0.8759 0.1948 0.9049 0.7112 0.8010 0.5468 0.0377 0.7212
0 1.0000 0 0 0 0 0 0 0 0
0 0 1.0000 0 0 0 0 0 0 0
0 0 0 1.0000 0 0 0 0 0 0
0 0 0 0 0 0 1.0000 0 0 0
1.0000 0 0 0 0 0 0 0 0 0
0 0 0 0 0 1.0000 0 0 0 0

Weitere Antworten (0)

Produkte


Version

R2019a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by