Replace string and then place it again

Hey, I want to make the output return # as many times as a certain string has, and then, change each # with the corresponding letter in the original string to get a cool ouput.

This is my code so far but I got stuck:

function a = jamstr(strd,time)
for i = 0:1:length(strd)
    z = i + 1;

    expression = '^.*'; 

    replace = '#';
    newStr = regexprep(strd(z),expression,replace)
    fprintf(newStr);
    pause(time);
    a=z;
    if z == length(strd)
        break
    end
end
end

[BobH]

I'm having difficulty understanding what you're asking.

- what would a sample 'strd' look like?

- what do you want the corresponding 'a' to look like?

[Mansour Al Asais]

jamstr('Matlabl rocks!',0.1)

What do you mean?

[Ameer Hamza]

Mansour, what is the expected output for

jamstr('Matlab rocks!',0.1)

Answer 1

[BobH]

This is intentionally backwards from what you asked; adjusting it to start with all '#' is for you

helpful: https://www.mathworks.com/matlabcentral/answers/348090-how-do-i-overwrite-text-in-the-command-window

https://www.mathworks.com/matlabcentral/answers/372643-is-it-possible-to-rewrite-update-a-printed-line

function a = jamstr( strd, time )

    fprintf( '%s', strd );  % print the entire string

    % one backspace for each char
    bkspaces = repmat('\b',size(strd));
    fmt = [bkspaces '%s'];  % format string for fprintf
    
    for i = 1:length(strd)
        newStr = strd;
        newStr(i) = '#';
        
        fprintf( fmt, newStr );
        
        pause(time);
    end
    
    fprintf( fmt, strd );  % restore original
    fprintf( '\n' );  % end on a fresh line
end