Looping over a double

I have a double with 2808 time values stored in it. I want to loop it over a function where every iteration the time changes to the next time minus the first.. nth time minus the first time.

This is the eq: 1/(j+1) where j is the time value that would change every iteration and store value, index.

This is what I currently have:

time = a double with 2808 time values

for i = 1:size(time)

a(i) = i-7.3457e+05; %a is double storing time since mainshock

end

for j = 0:size(a)

aa(j+1) = 1/(j+1); %this is the eq I want to implement

end

Answer 1

[David Hill]

I think this is what you are asking for.

time=time-time(1);
aa=1./time;

[Marcos Perez Rodriguez]

Yes! Thank you!